Hacker Newsnew | past | comments | ask | show | jobs | submitlogin
Thoughts about Pi (colorforth.com)
36 points by wkoszek on April 14, 2016 | hide | past | favorite | 11 comments


Diameters might appear in drawings. But they NEVER appear in physics. (The distance between particles determines forces. Diameters are a boring parameter about the size of something.) Machine tool programming is mostly radii in the paths, and diameters in the setup parameters.


> Diameters might appear in drawings. But they NEVER appear in physics.

Even as a characteristic size in, say, Reynolds number definition?


The statement about the diameter being the interesting parameter is kind of exactly wrong. This is true for all the same reasons Tau is a better constant than Pi.

For example, how does one derive the area of a circle? The most natural way is to integrate with respect to radius. When using Tau and radius, you get A = (1/2)Taur^2, which is nice since it looks a lot like the integral of, say, momentum, which gives you kinetic energy. If you use Pi or diameter or both, then weird factors of 2 start to creep in. It's also much more natural to think about defining the radial extent at each angle, rather than the diameter, especially if you're dealing with something other than a circle that has changing radius.


Tau is not happening.


I'll echo what gp said to help make tau happen:

tau : the circumference (perimeter) of a circle.

(1/2)tau^2 : the area of a circle.

Beautiful. To go from one to the other, you integrate or take a derivative. Like gp said, there's no weird factor of two. Just the power rule in action.


(1/2)tau^2? I assume that's not what you meant to write, and just mention:

2pi r : the circumference (perimeter) of a circle.

pi r^2: the area of a circle.

Beautiful. To go from one to the other, you integrate or take a derivative. There's no weird factor of 1/2. Just the power rule in action.


You seem to have left out the r in both of those expressions.

Tou r. .5 tou r^2 .


Nope, all circles have a perimeter of 19.7392088022.


Stop trying to make tau happen. It's not going to happen.


Yeah but the radius of the moon's orbit is sure interesting.


Your conjecture as to the surface area of a hypersphere embedded in 4 dimensions (a "3-sphere") is not borne out :) The answer is in fact d^3 pi^2 / 4. See https://en.wikipedia.org/wiki/N-sphere#Volume_and_surface_ar...




Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: